i want this cpp code in python

i have tried below as python but got error while calling result = kth_element_finder(arr1,arr2,arr1+10,arr2+5,k)

i want the given cpp code in python, can you help me out on this please

cppcode:

int kth(int *arr1, int *arr2, int *end1, int *end2, int k){
    if (arr1 == end1)
        return arr2[k];
    if (arr2 == end2)
        return arr1[k];
    int mid1 = (end1 - arr1) / 2;
    int mid2 = (end2 - arr2) / 2;
    if (mid1 + mid2 < k){
        if (arr1[mid1] > arr2[mid2])
            return kth(arr1, arr2 + mid2 + 1, end1, end2,
                k - mid2 - 1);
        else
            return kth(arr1 + mid1 + 1, arr2, end1, end2,
                k - mid1 - 1);
    }
    else{
        if (arr1[mid1] > arr2[mid2])
            return kth(arr1, arr2, arr1 + mid1, end2, k);
        else
            return kth(arr1, arr2, end1, arr2 + mid2, k);
    }
}
int main(){
    int arr1[5] = {2, 3, 6, 7, 9};
    int arr2[4] = {1, 4, 8, 10};
    int k = 8;
    cout << kth(arr1, arr2, arr1 + 5, arr2 + 4, k);
    return 0;
}

converted python code which has the error

def kth_element_finder(arr1,arr2,end1,end2,k):
    if(arr1 == end1):
        return arr2[k]
    if arr2 == end2:
        return arr1[k]

    mid1 = (end1 -arr1) / 2
    mid2 = (end2 - arr2) / 2

    if (mid1 + mid2) < k:
        if arr1[mid1] > arr2[mid2]:
            return kth_element_finder(arr1,arr2 + mid2 + 1, end1 , end2, k - mid2 -1)
        else:
            return kth_element_finder(arr1+mid1+1,arr2, end1 , end2, k - mid1 -1)
    else:
        if arr1[mid1] > arr2[mid2]:
            return kth_element_finder(arr1,arr2,arr1 + mid1 , end2, k)
        else:
            return kth_element_finder(arr1,arr2,end1 ,arr2+mid2, k)


arr1 = [4,5,7,3,2,0,1,100,55,12]
arr2 = [6,1000,99,8,60]
k = 2
print(len(arr1))
print(len(arr2))

result = kth_element_finder(arr1,arr2,arr1+10,arr2+5,k)
print(result)