Passing a value from a drop-down list to a SELECT statement

Hello, I am new to this site and to php and mySQL...and I need some help. I know this topic is all over the web but after a couple of days of looking and refering to several text books it still doesn't work so please bear with me.

I have created a web page with an associated mySQL database for our local women's golf club. I am trying to create a routine that will allow active members to get a web page displaying a listing of other members who live near them (in the same city/town). I have created a drop-down list in file 1 (memberSelect.php) with the following code below.

I want to pass the the value selected (town) to file 2 (activeMemberListing_NearMe.php) using the POST method. The code in file 2 is as follows below.

The While loop processes query results and displayes all records found. Note - I know this while loop works as it is taken from another file that successfully calls a SELECT statement and simply lists all active members of the club.

When I open file 1, select a city and click the "List Members" button I end up right back at file 1. This leads me to believe that I am passing nothing with the the "IF($cityID == 0)" code line in file 2 being true and thereby returning me to file 1.

I know this is a static selection list but before I move to a dynamic selection list I want to know why this doesn't work. Any help will be greatly appreciated.

Kathy

File 1
<?php

        //  2nd select routine

        echo' <form action="activeMemberListing_NearMe.php" method="post">';
        echo'   <table> <tr> <td>';

        echo'             <select name="town">';
        echo'               <option value="0" name="town" selected="selected">...Select City...</option>';
        echo'                 <option value="Carson City">Carson City</option>';
        echo'                 <option value="Gardnerville">Gardnerville</option>';
        echo'                 <option value="Markleeville">Markleeville</option>';
        echo'                 <option value="Minden">Minden</option>';
        echo'                 <option value="Smith">Smith</option>';
        echo'                 <option value="South Lake Tahoe">South Lake Tahoe</option>';
        echo'                 <option value="Stateline">Stateline</option>';
        echo'                 <option value="Wellington">Wellington</option>';
        echo'                 <option value="Zepher Cove">Zepher Cove</option>';
        echo'             </select>';               
        echo'           </td> <td></td> <td>';
        echo'             <input type="submit" value="List Members" />';
        echo'           </td> </tr> </table>';  
        echo' </form>';

    ?>      

File 2

 if($dbSuccess)
        {
              //  Get the details of the member's form the selected city 
            $cityID = $_POST["town"];   
            if ($cityID == 0) 
             {
                echo "<script type='text/javascript'> document.location = 'memberSelect.php'; </script>";
             }   // end if          

          $activeMembersNearMe_SQLselect = "SELECT FirstName, FullName, Address, City, State, Zip, HomePhone, CellPhone, Email, Picture ";
          $activeMembersNearMe_SQLselect .= "FROM ";
          $activeMembersNearMe_SQLselect .= "members ";
          $activeMembersNearMe_SQLselect .= "WHERE Status = 'Active' AND City = '".$cityID."' ";
          $activeMembersNearMe_SQLselect .= "ORDER BY FirstName , LastName ";

          $activeMembersNearMe_SQLselect_Query = mysqli_query($dbConnected,$activeMembersNearMe_SQLselect); 

          $index = 1;

          while ($row = mysqli_fetch_array($activeMembersNearMe_SQLselect_Query))