Month: April 2021

Basically this scheme uses variable offsets, but it generates the bytes on the fly. They aren't truly random, but there aren't any obvious patterns and the output passes all the NIST tests.

Since a simple password can be used to do the de/encryption it is much easier to hand off to the recipient and any good password generator can create one.

Since only part of the generated sub keys are used, it becomes very difficult if not impossible to reverse engineer the sub key to find the previous or next sub key.

def Count_Total_Words(str1):
total = 1
for i in range(len(str1)):
    if(str1[i] == ' ' or str1 == '\n' or str1 == '\t'):
        total = total + 1
return total

string = input("Please Enter your Own String : ")
leng = Count_Total_Words(string)
print("Total Number of Words in this String = ", leng)

So we can't just do the top half of the shape, then do another bunch of loops as the opposite to output the second half of the shape. This is what i did, but i'm told it can be done in no more than 3 loops. I can't quite figure out how though and i'm intrigued!

This is how it should look:

  *********
    *******
      *****
        ***
          *
        ***
      *****
    *******
   *********



    void draw3c()
{
    for (int i = 0; i <= 4; i++ )
    {
        for (int j = 0; j < i; j++)
            cout << " ";
        for (int s = 0; s < 9 - (i * 2); s++)
            cout << "*";
        for (int j = 0; j < i; j++)
            cout << " ";
        cout << "\n";
    }
    for (int i = 0; i < 4; i++)
    {
        for (int j = 0; j < 3 - i; j++)
            cout << " ";
        for (int s = 0; s < 3 + (i * 2); s++)
            cout << "*";
        for (int j = 0; j < 3 - i; j++)
            cout << " ";
        cout << "\n";
    }
    }

Mr.Sadik and Ramadan are competing together, both of them wants to become expert on Codeforces first.

You will be given two numbers R1 and R2, where R1 is the current rate of Mr.Sadik and R2 is the current rate of Ramadan.

Can you determine who will become expert first after adding X1 to Mr.Sadik rate and adding X2 to Ramadan rate.

Note that the rate must reach 1600 to become an expert.

Input
You will be given two lines. The first line will be current rates R1 and R2 where (0R1,R2106).

The second line will be additonal rates X1 and X2 where (0X1,X2106).

Output
Print Mr.Sadik if he became expert first otherwise print Ramadan.

If they both became expert print the one who has higher rate.

If none of them became expert print None.

I would like a help from someone who knows how to ...

I want a PHP Search that does sarch for a specific keyword or something inside a directory with full of .txt files and gives the output of all Searched files with matched words with a Link where you can vist ! if someone has the time and willing to help me thank you very much in regards :)